Using Opendir() With My Url php syntax question

niplore · August 7th, 2003, 8:55 AM

im trying to create a thumbnail gallery and im starting out with the basics, I want use the following code to set the dirrectory to my images folder. If my images were located at www.mysite.com/images how would the following code go

$handle = opendir(???????) or die("cannot open directory");

tekdoctor · August 7th, 2003, 4:39 PM

$config['albumdir'] = "/Photoalbum/albums/";
$config['fullpath'] = "/home/username/www/$config[albumdir]";

$dir = opendir("$config[fullpath]$filepath");

Something like that..

niplore · August 7th, 2003, 8:31 PM

That worked, thanx a bunch

:worship: :worship:

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August 7th, 2003, 8:55 AM	#1 (permalink)
niplore Registered User Fresh Surpasser Joined in Aug 2003 5 posts Gave thanks: 0 Thanked 0 times	im trying to create a thumbnail gallery and im starting out with the basics, I want use the following code to set the dirrectory to my images folder. If my images were located at www.mysite.com/images how would the following code go $handle = opendir(???????) or die("cannot open directory");

August 7th, 2003, 4:39 PM	#2 (permalink)
tekdoctor Registered User Fresh Surpasser Joined in Aug 2003 Lives in St. Louis, MO USA 26 posts Gave thanks: 0 Thanked 0 times	$config['albumdir'] = "/Photoalbum/albums/"; $config['fullpath'] = "/home/username/www/$config[albumdir]"; $dir = opendir("$config[fullpath]$filepath"); Something like that..

August 7th, 2003, 8:31 PM	#3 (permalink)
niplore Registered User Fresh Surpasser Joined in Aug 2003 5 posts Gave thanks: 0 Thanked 0 times	That worked, thanx a bunch :worship: :worship:

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