PHP update to 7.5 - PhpNuke that is

Armageddon · October 6th, 2004, 12:47 PM

I just updated my site from 7.0 to 7.5

as it turns out that until 2 days ago I was running 7.4, I usually run the site for 2 to 3 days to make sure everything is ok and test everything with no problem for every update that has come out and I know all ready how to do the updates with no problem.

However now that I installed 7.5 everything was ok till I apply the new 7.5 patch to avoid SQL injection, now I get this error when I try to work on the forums

(You are not authorised to administer this board).

I read every readme file that I found over and over looking to see what went wrong or if I forgot something to upload or to edit with no success.

Also when I try to access a new feature that was added with 7.5 (_SECTIONSMANAGER) I get another error message.

Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /home/ericore/public_html/sentinel/includes/sql_layer.php on line 286
Access Deniedr = dir("admin/case"); while($func=$casedir->read()) { if(substr($func, 0, 5) == "case.") { include($casedir->path."/$func"); } } closedir($casedir->handle); $result = $db->sql_query("SELECT title FROM ".$prefix."_modules ORDER BY title ASC"); while ($row = $db->sql_fetchrow($result)) { if (file_exists("modules/$row[title]/admin/index.php") AND file_exists("modules/$row[title]/admin/links.php") AND file_exists("modules/$row[title]/admin/case.php")) { include("modules/$row[title]/admin/case.php"); } } break; } } else { switch($op) { default: login(); break; } } ?>

I'm not a sharp one when it comes to SQL .

Have anyone have this error and how can I fix this. Thanks

**sam** · October 6th, 2004, 12:50 PM

i presume you mean phpnuke - not php? php is on release 5.

i'm moving the thread to another thread so others see it more easily.

Armageddon · October 6th, 2004, 12:53 PM

Yes PHP-Nuke

**patrickb** · October 6th, 2004, 2:15 PM

Honestly, I think you might be better off seeking this answer from PHPNuke's support in this case. Maybe someone here will know the answer but since this is their patch, it is quite likely they can answer you much faster. The SQL error generally means the mysql query wasn't valid and caused an error. It could be anything from a missing table in the database that needs to be added to support the new feature, to a simple typo in their code somewhere.

October 6th, 2004, 12:47 PM	#1 (permalink)
Armageddon Registered User Fresh Surpasser Joined in Jun 2004 Lives in In a galaxy far far away 16 posts Gave thanks: 0 Thanked 0 times	PHP update to 7.5 I just updated my site from 7.0 to 7.5 as it turns out that until 2 days ago I was running 7.4, I usually run the site for 2 to 3 days to make sure everything is ok and test everything with no problem for every update that has come out and I know all ready how to do the updates with no problem. However now that I installed 7.5 everything was ok till I apply the new 7.5 patch to avoid SQL injection, now I get this error when I try to work on the forums (You are not authorised to administer this board). I read every readme file that I found over and over looking to see what went wrong or if I forgot something to upload or to edit with no success. Also when I try to access a new feature that was added with 7.5 (_SECTIONSMANAGER) I get another error message. Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /home/ericore/public_html/sentinel/includes/sql_layer.php on line 286 Access Deniedr = dir("admin/case"); while($func=$casedir->read()) { if(substr($func, 0, 5) == "case.") { include($casedir->path."/$func"); } } closedir($casedir->handle); $result = $db->sql_query("SELECT title FROM ".$prefix."_modules ORDER BY title ASC"); while ($row = $db->sql_fetchrow($result)) { if (file_exists("modules/$row[title]/admin/index.php") AND file_exists("modules/$row[title]/admin/links.php") AND file_exists("modules/$row[title]/admin/case.php")) { include("modules/$row[title]/admin/case.php"); } } break; } } else { switch($op) { default: login(); break; } } ?> I'm not a sharp one when it comes to SQL . Have anyone have this error and how can I fix this. Thanks __________________ Site Address: www.ericore.com IP: 72.29.90.27 Hostname: Server.CVSDesigns.com Last edited by Armageddon; October 6th, 2004 at 12:54 PM..

October 6th, 2004, 12:53 PM	#3 (permalink)
Armageddon Registered User Fresh Surpasser Joined in Jun 2004 Lives in In a galaxy far far away 16 posts Gave thanks: 0 Thanked 0 times	Yes PHP-Nuke __________________ Site Address: www.ericore.com IP: 72.29.90.27 Hostname: Server.CVSDesigns.com

October 6th, 2004, 2:15 PM	#4 (permalink)
patrickb the one who was Super #1 Joined in Jul 2003 Lives in Memphis 1,967 posts Gave thanks: 0 Thanked 3 times	Honestly, I think you might be better off seeking this answer from PHPNuke's support in this case. Maybe someone here will know the answer but since this is their patch, it is quite likely they can answer you much faster. The SQL error generally means the mysql query wasn't valid and caused an error. It could be anything from a missing table in the database that needs to be added to support the new feature, to a simple typo in their code somewhere. __________________ Patrick Warnings: The program(s) might crash unexpectedly or behave otherwise strangely. (But of course, so do many commercial programs on Windows.) --www.gimp.org

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October 6th, 2004, 12:50 PM	#2 (permalink)
sam Surpass Fan Super #1 Joined in Dec 2003 Lives in NJ 5,057 posts Gave thanks: 0 Thanked 4 times	i presume you mean phpnuke - not php? php is on release 5. i'm moving the thread to another thread so others see it more easily.

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